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Mathematics
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CIRCLES. everything that I post today will be about circles.
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you can do 16 yourself ... right
Yeah, it's 15 that stumps me.
ignore the quadrilateral ... find the angles you want by the arc they are opposite
I get a weird answer.
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what do you get for x?
36.5
how?
by solving it wrong lol. Can you explain?
how did you try to solve it?
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just the x...
wait 36.5 is right.... for y
I added 96+48+45/2 and subtracted it from 360.
so x is 72?
for x, i use: \[m \angle G = \frac 12\cdot m \arc FEH\]
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\[12x = \frac 12 (96+48)\]
94.5?
??? x=6
ok ... 12x=72
Wait, I'm confused
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sorry, \[\Large m \angle G = 12 x = 72\] so, x= 6
And one more question!
sure
Is 16 2x+11=4x-3?
yes
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