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Mathematics 22 Online
OpenStudy (anonymous):

CIRCLES. everything that I post today will be about circles.

OpenStudy (anonymous):

OpenStudy (paxpolaris):

you can do 16 yourself ... right

OpenStudy (anonymous):

Yeah, it's 15 that stumps me.

OpenStudy (paxpolaris):

ignore the quadrilateral ... find the angles you want by the arc they are opposite

OpenStudy (anonymous):

I get a weird answer.

OpenStudy (paxpolaris):

what do you get for x?

OpenStudy (anonymous):

36.5

OpenStudy (paxpolaris):

how?

OpenStudy (anonymous):

by solving it wrong lol. Can you explain?

OpenStudy (paxpolaris):

how did you try to solve it?

OpenStudy (paxpolaris):

just the x...

OpenStudy (paxpolaris):

wait 36.5 is right.... for y

OpenStudy (anonymous):

I added 96+48+45/2 and subtracted it from 360.

OpenStudy (anonymous):

so x is 72?

OpenStudy (paxpolaris):

for x, i use: \[m \angle G = \frac 12\cdot m \arc FEH\]

OpenStudy (paxpolaris):

\[12x = \frac 12 (96+48)\]

OpenStudy (anonymous):

94.5?

OpenStudy (paxpolaris):

??? x=6

OpenStudy (paxpolaris):

ok ... 12x=72

OpenStudy (anonymous):

Wait, I'm confused

OpenStudy (paxpolaris):

sorry, \[\Large m \angle G = 12 x = 72\] so, x= 6

OpenStudy (anonymous):

And one more question!

OpenStudy (paxpolaris):

sure

OpenStudy (anonymous):

Is 16 2x+11=4x-3?

OpenStudy (paxpolaris):

yes

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