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simplify. 2-2ln(2)
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4e^(-2ln(2)/3)=4e^((-ln(2^2)/3) [u know, rlna=ln(a^r) ] =4e^((-ln(4))/3) = 4*(e^(-ln4))^(1/3) = 4*(e^(ln(1/4)))^(1/3) =4*(1/4)^(1/3) [b/c e^lna = a] =4^(2/3) This is the most simplified expression. Now are you ok with it? source: http://answers.yahoo.com/question/index?qid=20081119170931AAEsaTw
that really makes no sense to me
Ok, I'll try to help.
We have a couple of laws for simplifying logarithms.
Namely, log(xy)=log x +log y
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log(x/y)=log y- log x
These apply to any base.
okay, but there's only one value in the ln function
|dw:1335934739115:dw| i don't know how else to simplify this except writing it out as 1 natural log. the problem, as given, is basically simplified.
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