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Factor completely. 3x^3 + 9x^2 + x + 3
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do you know synthetic division?
You do not need to use synthetic division?
no sir .
I know. :P pull out a x+3 from the first and second grouping, grouped as such (3x^3 + 9x^2) + ( x + 3)
(x+3)(3x^2+1) + (x+3)(1) you will have to factor the first part of this grouping, but it is a much easer factor (trinomial factor) than the original equasion.
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Now pull an (x+3) from both. (x+3)(3x^2+1) *answer!
THANK YOU ! <33333 :D
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