derivative of 2 sin 8x?
is 2 (8 cos 8 x)?
Yep! Nice work. You can go ahead and simplify that to 16 cos 8x.
what if i want to find the average value of it on interval [-pi,pi]?
Are you familiar with the Mean Value Theorem?
no :(
looking it up now
Are you supposed to find the average value of \(f\) or of \(f'\)?
of f. answer is 16/pi?
average value formula and mean value theorem call for derivative of f anyways
answer is not 16/pi after all..
I was going to say, I've been doing this a variety of ways and keep getting an average value of zero
i got zero, too.
Pretty sure zero's the right answer :)
it is. what a strange-seeming answer
Not at all! It's perfectly intuitive. The endpoints of the interval are both 0, and it's a sine wave in between.
Spends the same amount of time above the axis as it does below the axis, if that makes sense.
ohh. ok. thank you again :-)
Sure thing :)
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