Help please
with what
Find the distance between the two points. Round to the nearest tenth if necessary. (8, 8), (12, 11) (1 point) 7 5 25 28
I need help with a few other things, can you please stay and help me?
what are the last four numbers for?
those are the options for the answers
?
Here's more Find the distance between the two points. Round to the nearest tenth if necessary. (–2, –6), (3, 9) (1 point) 15.8 250 3.2 20
D = square root((12-8)^2 +(11-8)^2 ) D = square root(16+9) = 5 Answer = 5 units
Thanks , here's another one. Find the perimeter of triangle CDE. Round to the nearest tenth. https://www.connexus.com/content/media/102877-3182010-93934-PM-1187492183/res00000/ppg/examview/images/mc010-2.jpg 90.0 18.0 14.3 10.5
you need to find the distance between each pair of points, then add them all up
so what is the distance between point C and point D ?
So what wouuld the answer be?
you'll be able to tell me if you let me teach you how to solve the problem
I haven't checked myself, so I'll just walk through it with you step by step
@Missoyo thats the only way your going to learn it
okayy
math is to complicated for ,me :(
I understand, but you need to take it slowly that's how math is so what are the coordinates of point C ?
I understand that but it takes practice sometimes we actually make things are than they really are
-3 , 3 ?
-3 , 1 ? sorry.
right :) and point D ?
4, 1 ? :)
almost remember x-coordinate is first y is second
so it would 1,4 ?
right! so the top side of the triangle would be the distance between points (-3,1) and (1,4). if we had walked you through the earlier problems this part would be easy, but I'm guessing you can't find that distance yet, right?
Yes correct. I need alot of help :/ and this is a big grade , I really need to pass.
If you want to pass please try not to ask for only answers all that gets you is a guaranteed F on the final exam so finding the distance between two point.... do you know the pythagorean theorem?
Your right, I regret it now & No I don't.
for any right triangle|dw:1335982603211:dw|the length of the hypotenuse \(c\) in relation to its sides \(a\) and \(b\) is given by the formula\[c^2=a^2+b^2\]ring a bell? if not you will just have to memorize a slightly harder formula...
Yes I seen something like that
now think about two points which have some coordinates \((x_1,y_1),(x_2,y_2)\) as being at each end of the hypotenuse|dw:1335982984200:dw|this means we can find the length of each leg, since the vertical is given by the difference in the \(y\) coordinate \(y_2-y_1\), and the horizontal length is given by the difference in the x-coordinate\(x_2-x_1\)
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