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1.What is the sum of the geometric sequence 8, –16, 32 … if there are 15 terms? with work ? please
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262136 is the answer ?
\[r=-2\] it looks like
thank you guys
No it's this The first term is 8, and the second is -16 Thus, this is a sum of the form (8)(-2)^n we have: Summation of 8(-2)^n from n = 0 to n = 14 = 8 [Summation of (-2)^n from n = 0 to n = 14] = 8 [((-2)^(15) - 1) / (-2 - 1)] = 87384
so you have \[8(1+(-2)+(-2)^2+(-2)^3+...+(-2)^{14}\]
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okay
end up with \[8\times \frac{(-2)^{15}-1}{-2-1}\] if a remember correctly
what jackie said
so the answer is 87384 ?
yes i believe so.
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thank you
no problem
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