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Part 1: Find the polynomial f(x) that has the roots of –2, 3 of multiplicity 2. (4 points) Part 2: Explain how you would verify the zeros of f(x). (4 points)
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A polynomial having two roots can be written as \[(x-a)^p(x-b)^q\] where a-->first root b-->second root. p-->multiplicity of root a q-->multiplicity of root b Given p=1 and q=2 and the roots are a=–2, b= 3 Can you substitute and simplify the polynomial now??
For part 2: After you get the polynomial from the part 1. Substitute 1) x = -2 you will get the polynomial value as 0 2)Similarly substitue the second root in place of x and you should get polynomial value as 0 In case of any doubt, post it here :)
Okay thank you
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