Consider the following series of reactions (unbalanced). Starting with 3.0 moles of ammonia, (and excess of the rest of the reactants), how many moles of calcium nitrate could be obtained? (assume 100% yield)
NH3 +O2 →N2O5 +H2O
N2O5 + H2O → HNO3
HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O

Tell me if I am right. Use hess's law cancel out all of that stuff then balance the equation to get

2NH3 +2O2 + Ca(OH)2- Ca(NO3)2+4H2O

Then use the molar relationship to get 1.5 moles

Question

Consider the following series of reactions (unbalanced). Starting with 3.0 moles of ammonia, (and excess of the rest of the reactants), how many moles of calcium nitrate could be obtained? (assume 100% yield)
NH3 +O2 →N2O5 +H2O
N2O5 + H2O → HNO3
HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O

Tell me if I am right. Use hess's law cancel out all of that stuff then balance the equation to get 

2NH3 +2O2 + Ca(OH)2-> Ca(NO3)2+4H2O 

Then use the molar relationship to get 1.5 moles

anonymous · Answer

Correct as far as I'm concerned ;]

anonymous · Answer

sweet thanks!