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Mathematics 20 Online
OpenStudy (anonymous):

Find the area under the curve y = 2x^2 - x^2 from x =1to x = 2 .

OpenStudy (anonymous):

integrate from 1 to 2

OpenStudy (anonymous):

so y=x^2?

OpenStudy (anonymous):

∫(2x^2-x^2)dx from 1 to 2 Therefore ∫(x^2)dx, thus [(1/3)x^3] from 1 to 2 8/3-1/3 The answer is 7/3.

OpenStudy (kropot72):

Is theequation of the curve as follows? \[y=2x ^{2}-x ^{2}\]

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