Antiderivative of 1/x^2

Question

anonymous · Answer

1/(x^2) = x^(-2)
hence, antiderivative = x^(-1)/ -1 = -x^(-1) or -1/x + c

c = integration constant

lgbasallote · Answer

change it to negative exponent then put it on top then integrate by power rule

anonymous · Answer

THANK YOU:D

anonymous · Answer

What about 1/2x+3? Im confused about this one

lgbasallote · Answer

this is all yours @Rohangrr

anonymous · Answer

@lgbasallote  wat??

inkyvoyd · Answer

He's saying, don't you copy paste ever again.

lgbasallote · Answer

btw..while you're at it there's this problem confusing me...a quite similar one...how to integrate 

$\LARGE \int e^{x^{-2}} dx$

i think it has something to do with u-substitution as well....

anonymous · Answer

@inkyvoyd just say quiet if you aren't answering

mimi_x3 · Answer

igbiw that's an error function..

inkyvoyd · Answer

I encourage you guys to report this blatant plagiarizer http://answers.yahoo.com/question/index?qid=20090119012032AAtrnFc.

lgbasallote · Answer

oh....no wonder i cant get it :/

inkyvoyd · Answer

@lgbasallote , stop faking xD

mimi_x3 · Answer

i think that is thhe one used in statistics.

lgbasallote · Answer

hahahaha =))))) well i really couldnt get it :P and btw...the question was deleted...

inkyvoyd · Answer

@Mimi_x3 , it's used in a lot of things

kinggeorge · Answer

This link works though http://answers.yahoo.com/question/index?qid=20090119012032AAtrnFc

lgbasallote · Answer

"1/(x^2) = x^(-2)
hence, antiderivative = x^(-1)/ -1 = -x^(-1) or -1/x + c

c = integration constant"

copied straight from it...does look familiar....

lgbasallote · Answer

(spacings included)

inkyvoyd · Answer

Huh. The question is the exact same too.

lgbasallote · Answer

no...the question had parenthesis...or  did it...?