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Mathematics 22 Online
OpenStudy (anonymous):

root x?

OpenStudy (anonymous):

\[\sqrt{x}\]

OpenStudy (anonymous):

?

OpenStudy (anonymous):

What exactly are you asking?

OpenStudy (anonymous):

differentiate it?

OpenStudy (anonymous):

\[1\div2\sqrt{x}\]

OpenStudy (mimi_x3):

Write it as: \[\large x^{1/2}\] then apply the chain rule.

OpenStudy (anonymous):

OK, root x = x^1/2 d/dx x^1/2 = (1/2)x^-(1/2) = 1/2*x^1/2 \[=\frac{\sqrt{x}}{2x}\]

OpenStudy (anonymous):

i hav taken bio so, i don't know chain rule.

OpenStudy (anonymous):

hw u get 1/2

OpenStudy (anonymous):

d/dx x^y = yx^(y-1) right? so in this case y = 1/2 (sqrt means the 1/2 power)

OpenStudy (mimi_x3):

\[\huge \frac{d}{dx}=\frac{1}{2} x^{\frac{1}{2}-1} =>\frac{1}{2} x^{\frac{-1}{2}} \]

OpenStudy (anonymous):

Yeah then put in surd form and rationalise

OpenStudy (anonymous):

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