Question

limx-0 [x^2/sinxtanx] where [.] denotes greatest integer function
answer is zero but i want the method to solve this problem

Answer 1

maybe L'hopital's I tried it without breaking up tanx into sinx/cosx but that didn't work maybe try breaking it up to get x^2/(sin^2x/cosx)

Answer 2

looking easy but it is difficult

Answer 3

\[
\frac {x^2} {\sin x \,\tan x}= \frac{x} {\sin x} \frac{x} {\tan x}
\]
So the limit is 1 since each factor of the product above goes to 1 when x goes to zero.