Use the quadratic formula to find the roots of the equation. Round to tenths place if necessary.
11x2 - x - 3 = 0
A. {-1, 1.2}
B. {-11, 13.2}
C. {-0.5, 0.6}
D. no real solution

Question

Use the quadratic formula to find the roots of the equation. Round to tenths place if necessary.
11x2 - x - 3 = 0
A. {-1, 1.2}
B. {-11, 13.2}
C. {-0.5, 0.6}
D. no real solution

anonymous · Answer

you have a equation in the form ax^2 + bx + c  so a=11  b=-1 c=-3 plug these values into the formula $$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

anonymous · Answer

$$
 b^2 -4 a c =133>0
$$
We have two real roots. Find them using the formula that @Tyler1992 gave you above.

anonymous · Answer

$$-(-1)\pm \sqrt{-1 -4(11)(-3)}$$

anonymous · Answer

over 2(11)

anonymous · Answer

good now you just have to simplify and you're done

anonymous · Answer

$$\frac{-(-1) \pm \sqrt{(-1)^2 - 4(11)(-3)}}{2(11)} = \frac{1 \pm \sqrt{133}}{22}$$

anonymous · Answer

0.5

anonymous · Answer

0.5,0.6

anonymous · Answer

the answers should be -5, and 6   not .5 and .6 so im guessing its a typo in the choices