Find the equation of the line tangent to the following curve at the point (1,1). e+3x=e^(x/y)+3. I have the derivative as (y e^(-x/y) (e^(x/y)-3 y))/x

Question

experimentx · Answer

is it $ e^{3x} = e^{x/y} + 3$ ??

experimentx · Answer

and also are you sure about the derivative??

anonymous · Answer

nope. the equation is as written and I'm not sure on the derivative or how to get the line

experimentx · Answer

well, have your ever done "implicit differentiation"??

experimentx · Answer

http://www.youtube.com/watch?v=sL6MC-lKOrw

anonymous · Answer

I think we're just starting implicit differentiation. I'll check out that video though and see if it helps

experimentx · Answer

yeah .. find that implicit differentiation, use it to find the solve at (1,1)
and slove y = mx + c <--- you know the value of m from differentiation.

anonymous · Answer

@experimentX still having no luck after watching khan vids. can you break it down?

anonymous · Answer

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