Question

Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary.
A. {-1.7, 2.3}
B. {-2.4, 2.4}
C. {-2.3, 0.8}
D. no real solution

Answer 1

a=2; b=3; c=6
formula is \[-b \pm \sqrt{b ^{2}-4ac}\]/2a
solve!!

Answer 2

\[-b \pm \sqrt{b ^{2}-4ac}/2a\]

Answer 3

\[\LARGE {x_{1/2}} = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]

Answer 4

so for this one: \[-3\pm \sqrt{-39}/4\]
there is no real solution b/c you cannot solve the sq. root of -39!!

Answer 5

ok

Answer 6

There is no actual solution