Question

15 ml of mixture of c2h4 and ch4 after oxidation with o2 gave 20ml ofco2 gas express the composition of the mixture in volume measure all volume measurements are at the same temperature and pressure?
options are
(a) 10ml c2h4,5ml ch4
(b)7.5 ml c2h4,7.5 ml ch4
(c)5 ml c2h4, 10 ml ch4
(d) 9 ml c2h4 ,6ml ch4

Answer 1

sorry i made a mistake, in calculation so i have to do it all over again...

Answer 2

i recalculated and answer is D for calculation you will have to wait a little bit cause i made a mess and need to rewrite it more nicely... :D

Answer 3

here's the explanation in a bit shortened version:

Answer 4

hey the answer is (C) but i dont know how to do it

Answer 5

can u recheck it

Answer 6

ok

Answer 7

Answer is C. You can do the problem using 10 and 5 mL as a start and find out how much CO2 is formed. This is an easier problem than the one you have written.

Understanding what you do that way should help you solve the original problem.

Answer 8

i just solved while keeping things simple

Answer 9

can u give the solved steps

Answer 10

Have you tried solving the problem in the direct way (knowing amount of reactants)?

Answer 11

@shameer1: Please, can you at least post the balanced equation(s) representing the transformation?

Answer 12

no need of posting anything just go through it i hope it will make you understand :)

Answer 13

KISS= keep it short and simple
hahaah

Answer 14

thats C2h4 .... looks like y in the picture :p

Answer 15

Ok, stoichiometric no for O2 in second line should be 3, but this has no impact on the result.

Answer 16

yes it should Have been 3 oh man

Answer 17

I solved it using n1 and n2. Then equations go:
n1 + n2 = 15
n1 + 2 n2 = 20
which leads to the same solution.