Question

Let A,B be the roots of the equation x^2-px+r=0 & A/2,2B be the roots of this equation x^2-qx+r=0. Then what is the value of {r} ?

Answer 1

in terms of????

Answer 2

In terms of p and q????

Answer 3

if a quadratic equation has roots \(r_1, r_2\) then it can be written as:\[(a-r_1)(x-r_2)=0\]use this to find your solution.

Answer 4

p & q.

Answer 5

sorry, first bracket should be \(x-r_1)\)

Answer 6

(5pq-q^2-4p^2)/9

Answer 7

Use this property to solve this sum
Sum of roots of quadratic equation

\[ax^2+bx+c=0\]

is -b/a

Answer 8

am i righr????

Answer 9

but how?

Answer 10

AB=r


A+B=p
A+4B=2q
solving above 2 we get
B=(2q-p)/3
A=4p-2q)/3
put value of A and B in top equation we get
r=(10pq-4q^2-4p^2)/9

Answer 11

but ans. is \[2/9(2q-p)(2p-q).\]

Answer 12

I have writen this only if u open the brackets

Answer 13

and which top eq. are u talking about?

Answer 14

AB=r

Answer 15

Oh ,I See Thanx a lot:)

Answer 16

it was pleasure nice question