Question

2x^2e^-x = 18e^-x

Answer 1

\(\large 2x^2 e^{-x} = 18e^{-x}\) is that it?

Answer 2

\[2x ^{2}e ^{-x}=18e ^{-x}\]

Answer 3

Yes

Answer 4

uhmmm see how e^-x is common to both sides of the equation?

Answer 5

Yes.

Answer 6

when you see those..your first thought should be to divide both sides

Answer 7

By e^-x to get rid of them?

Answer 8

yup

Answer 9

\[e^{-x} (x^2-9)=0\]
\[e ^{-x}=0\] No solution
(x+3)(x-3)=0
x=3,-3

Answer 10

there should be a coefficient of 2 in your e^-x...but still void haha

Answer 11

^that's another way to do it :D

Answer 12

Where did the 9 come from?

Answer 13

he did it like this

\(2x^2 e^{-x} - 18e^{-x} = 0\)

\(e^{-x} (2x^2 - 18) = 0\)

\(2e^{-x}(x^2 - 9) = 0\)

Answer 14

@lgbasallote You can just divide both sides by 2. No x terms.

Answer 15

yeah like i side wouldnt make a difference =))

Answer 16

said* lol what am i saying

Answer 17

ok cool... thank you.