Find the product. (Multiplying Rational Expressions) v - 12 over 10 times - v - 2 over 4 Help/an explanation would be greatly appreciated. :)
All you have to do is multiply the numerators and the denominators
I did that, but I got a completely different answer from the book, which has an answer key. I'm pretty sure I have to factor something, but I'm not sure. The book says the answer is \[-(v-3) \over 5(v+1)\].
can you show your work and what you got?
The drawing feature isn't being cooperative, but I'll try to explain it as best I can. I multiplied (v-12) and -v-2 and got v+24 over 40. And I'm somewhat stuck there right now.
i'm doing it out on on paper and i got (-v^2+10v+24)/40 so the answer in your bok is stumping me
Hm.. I'll keep trying. Maybe the answer was written incorrectly. Thanks for the assistance, though!
no problem. I'd suggest bumping this and see if anyone else can figure it out.
@ChukRock , I got the same thing you did. @Hologram are you sure that you copied the problem correctly from the book and that you are looking at the correct answer?
My question was a simplified version of the original problem, so it's likely that I simplified the problem incorrectly. Would it be better to post the original instead? Sorry for the confusion; this is a totally new concept.
Yes, try to post the original
Alright, the original is \[v ^{2}+v-12 \over 5v+1 \] times \[-v-2 \over v ^{2}+5v +4\].
Is the denominator of that first term 5v+1 or is it v+1?
Sorry, it's 5v+10. Missed that.
Ok, factor\[v ^{2}+v-12=\]and\[v ^{2}+5v+4=\] and \[5v+10=\] and plug back into the original equation. I think you will then get the answer from the book.
Thank you so much for your help!
you're welcome
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