Find the quadratic polynomial whose graph goes through the points (-1,4), (0,6), and (1,12).
f(x)= x^2+ x+

Question

Find the quadratic polynomial whose graph goes through the points (-1,4), (0,6), and (1,12).
f(x)= x^2+ x+

anonymous · Answer

y=(x-a)^2+h

4=r(-1-a)^2+h
6=r(0-a)^2+h
12=r(1-a)^2+h

anonymous · Answer

solve for r,a,and h

anonymous · Answer

ok

anonymous · Answer

someone help me with the ans, i keep getting the wrong ones..

anonymous · Answer

is that last part what the equation will look like? :  f(x)= x^2+ x+

anonymous · Answer

anonymous · Answer

it is not very hard to solve it by hand but it is long and tedious

anonymous · Answer

ok

anonymous · Answer

@rukh , is that last part, "f(x)= x^2+ x+", what the equation will look like?

anonymous · Answer

y=r(x-a)^2+h

anonymous · Answer

substitute the number in for r,a,h in

anonymous · Answer

ok