Question

Find the quadratic polynomial whose graph goes through the points (-1,4), (0,6), and (1,12).
f(x)= x^2+ x+

Answer 1

y=(x-a)^2+h

4=r(-1-a)^2+h
6=r(0-a)^2+h
12=r(1-a)^2+h

Answer 2

solve for r,a,and h

Answer 3

ok

Answer 4

someone help me with the ans, i keep getting the wrong ones..

Answer 5

is that last part what the equation will look like? : f(x)= x^2+ x+

Answer 6

http://www.wolframalpha.com/input/?i=Solve%5B4%3D%3Dr(-1-a)%5E2%2Bh%2C6%3D%3Dr(0-a)%5E2%2Bh%2C12%3D%3Dr(1-a)%5E2%2Bh%2C%7Br%2Ch%2Ca%7D%5D%7D%5D&t=crmtb01

Answer 7

it is not very hard to solve it by hand but it is long and tedious

Answer 8

ok

Answer 9

@rukh , is that last part, "f(x)= x^2+ x+", what the equation will look like?

Answer 10

y=r(x-a)^2+h

Answer 11

substitute the number in for r,a,h in

Answer 12

ok