an elevator is going down with a constant acceleration. A coin is dropped from a point 1.5m above the elevator floor takes one second to reach the floor. The magnitude of the acceleration of elevator is??? (g=10m/s2)

Question

experimentx · Answer

s = ut +(g-a)t^2, u =0
1.5 =  10-a, a = 8.5m/s^2

anonymous · Answer

hey ur answer is wrong option are (a) 3.6          (b) 5      (c)7.2      (d)6.4

experimentx · Answer

sorry for wrong formula
s = ut +1/2 *(g-a)t^2,

anonymous · Answer

then u=?????

experimentx · Answer

attachment

anonymous · Answer

how??

experimentx · Answer

|dw:1336272871420:dw|
Whenever body moves from rest, the initial velocity is 0

anonymous · Answer

in this question it is not mentioned it is on rest.......

experimentx · Answer

i don't think you can find if it is not given any value.

anonymous · Answer

the the answer is 6.4 but i dont know how to get it

anonymous · Answer

sorry my question was wrong