Need a confirmation on what I'm thinking :P

E.g.: I have $log_{3}243$
It could be written as $\huge \frac{log243}{log3}$, but also be written as $\huge \frac{ln243}{ln3}$
In this case, since there's no base, we took $\huge e$ as base, right?

Question

Need a confirmation on what I'm thinking :P

E.g.: I have $log_{3}243$
It could be written as $\huge \frac{log243}{log3}$, but also be written as $\huge \frac{ln243}{ln3}$
In this case, since there's no base, we took $\huge e$ as base, right?

anonymous · Answer

3 is the base so you would use log though... use ln when given a base of e

lgbasallote · Answer

seems to make sense

zepp · Answer

e as base like $\huge \frac{log_{e}243}{log_{e}3}=\frac{ln243}{ln3}$

zepp · Answer

kk cool.