Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to five.

Which equation could be used to determine the number?
1/2(n - 2) + 2/5 n = 5
1/2(n + 2) - 2/5 n = 5
1/2(n + 2) + 2/5 n = 5

Question

Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to five. 

Which equation could be used to determine the number?
1/2(n - 2) + 2/5 n = 5
1/2(n + 2) - 2/5 n = 5
1/2(n + 2) + 2/5 n = 5

parthkohli · Answer

$\Large \color{purple}{\text{n and n + 2 are the terms} }$
Now, can you do it?

anonymous · Answer

the big word to know here is difference, what does difference mean?

anonymous · Answer

difference in math mean to subtract, so you are subtracting these two terms.  Which is the only choice that does this?

anonymous · Answer

the bottom one

anonymous · Answer

If difference means to subtract then you need to have a minus sign between the two terms.  
So...
1/2(n + 2) - 2/5 n = 5