Question

prove:

Answer 1

\[\lim_{x \rightarrow 0}\sin x/x\]

Answer 2

L'Hopital rule.

Answer 3

lim as x tends to zero for sinx/x = = lim as x tends to zero of cosx/1 L'Hopitals

Answer 4

Technically that would do it for you, if you're allowed to assume L'hopital's.

Answer 5

do you know that the derivative of sine is cosine? if so, then this is the same as asking what is
\(\cos(0)\)
if not, then you have to use the old "squeeze" theorem. any book will have this proof

Answer 6

k!

Answer 7

absolutely no need for l'hopital here,
\[\lim_{x\to 0}\frac{\sin(x)}{x}=\sin'(0)=\cos(0)=0\] by the definition of the derivative

Answer 8

It is sandwich theorem for me :)), satellite73

Answer 9

k. Thanx!

Answer 10

@satellite73
cos0=1

Answer 11

ya anhkhoava! u r ryt.