Question

Find the solution to the equation 64^(x – 4) = 4^2x.

Answer 1

use log.

Answer 2

I knoww but after that i put it in log form i don't know what to do after.

Answer 3

Im not very good at Logs

Answer 4

to know about logs go to closed questions @nyan21

Answer 5

Take logs of both sides:
\[(x-4)\ln 64=2x \ln 4\]
\[\frac{\ln 64}{\ln 4}=\frac{2x}{x-4}\]

Answer 6

or write 64 as a power of 4 and use exponent properties\[64^{x-4}=(4^3)^{x-4}=4^{2x}\]now use the rule\[(x^a)^b=x^{ab}\]to simplify what you have and take log base 4 of both sides