Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Suppose a study of the faculty at U.S. medical schools revealed that 37% of the faculty were women and 63% were men. Of the female faculty, 31% were full/associate professors, 46% were assistant professors, and 23% were instructors. Of the male faculty, 51% were full/associate professors, 36% were assistant professors, and 13% were instructors. If a faculty member at a U.S. medical school selected at random held the rank of full/associate professor, what is the probability that the faculty member was female?

OpenStudy (slaaibak):

P(Female|FULL/ASSO) = P(FEMALE AND FULL/ASSO)/P(FULL/ASSO) P(Female + Asso) = 0.37 * .31 P(Full/asso) = .37 * .31 + .63 * .51

OpenStudy (slaaibak):

Meant to be P(Female + full/Asso) = 0.37 * .31

OpenStudy (anonymous):

.2630733945 Thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!