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Cut points of (x-2)(x+2)(3x-1)≤0: a. 2, -2, 3 b. 2, -2, -1/3 c. 2, -2, 1/3 d. 2, -2, -3
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Well, do you know what valeus of x will make (x-2)(x+2)(3x-1) 0?
(x-2)(x+2)(3x-1) = 0 is what I mean. What x values make that true?
Is the answer c.? I just need clarification
http://www.wolframalpha.com/input/?i=+%28x-2%29%28x%2B2%29%283x-1%29%E2%89%A40
Yes. But you probably didn't need to use Alpha. If you look at (x-2)(x+2)(3x-1) (x-2) = 0 gives me x=2 (x+2) = 0 gives me x=-2 (3x-1) = 0 gives me x=(1/3)
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Oh I see. Thank you for the explanation and the clarification!
You're quite welcome =)
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