-absolute value of x+2 (end of absolute value) +5 greater than or equal to 3
\[-|x+2|+5 \ge 3\]??
yes
r u there??
subtract 5 from both sides
i did that but that but i still dont understand!
what are you supposed to do? You just give us a problem, but no instructions.
i dont know! i dont understand what to do!
what are your insturctions? where did the problem come from?
are you solving for x, are you graphing? what?
my math book! it just says solve
ok, SOLVE FOR WHAT!!! what is the section title?
section title is:absolute value equations and inequalities
Ok, I think it wants the range of solutions. Do you have a final answer? If you do, this will be much easier, just don't give it to me until I'm done.
no its just multiple choice
Well, that's ok I guess. Here I go.
multiple choice answers are: A.\[3le x \le5\]. B.\[-1le x \le1\]. C.\[-4\le x \le0\] or D.\[-2\le x \le5\]
A.\[3\le x \le\]
\[-\left| x+2 \right|+5\ge3\] subtract 5 from both sides \[-\left| x+2 \right|\ge-2\] divide by negative \[\left| x+2 \right|\le2\] \[-2\le x+2 \le 2\] subtract 2 from all three sides \[-4 \le x \le 0\]
thank u!
Do I get a medal? lol
sure! lol!
YAY!
lol!
\[x^-2\] divided by 13xy^-2
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