Question

an object is launched upward at 45ft/sec from a platform that is 40 feet high.what is the obhect maximum height if the equation of height (h) in terms of time(t) of the object given by h(t) =-16y^2 + 45t + 40?

Answer 1

Did you mean for the y^2 to be t^2?

Answer 2

im sorry its suppose to be t^2

Answer 3

Just find the y coordinate of the vertex of your equation. That will be the maximum height

Answer 4

not quite understanding

Answer 5

Do you know that the equation you posted is the equation of a parabola?

Answer 6

no I didn't