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Mathematics 9 Online
OpenStudy (anonymous):

Vectors help needed. Please see the picture attached

OpenStudy (anonymous):

picture...

OpenStudy (anonymous):

OpenStudy (anonymous):

I am confuse how to find the angles for D and E

OpenStudy (anonymous):

and I actually dont really get B and C too :/

OpenStudy (anonymous):

E is obvious, isn't it? For D, I would use tangens...

OpenStudy (anonymous):

First, vectors go from the first letter to the second, so the vector between OB and OC is not 90, it should in fact be less. Second, because the sides are all the same, the angle should be half of 90.

OpenStudy (anonymous):

so that 90deg the angle in C..? i dont know which angle is it referring to

OpenStudy (anonymous):

oh, so is not 90..i wrote it wrong then

OpenStudy (anonymous):

Not for b, no. For part c, assuming that E is the midpoint, CE is 3 and OC is 6, so the angle should be cotan(3/6).

OpenStudy (anonymous):

oh ok i think i know what to do

OpenStudy (anonymous):

still dont know how to do between EO and Bo

OpenStudy (anonymous):

We know BOC and EOC, so to get BOE, subtract EOC from BOC.

OpenStudy (anonymous):

EOC i get 26degrees BOC i get 45 edeg so it is 19degs? but since it is not connected tail to tail i need to do 180- 19 right

OpenStudy (anonymous):

19 makes more sense if you look at the picture. 180-19 would give the angle as more than 90 degrees, which isn't possible in a square.

OpenStudy (anonymous):

ok , thanks then!

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