f^–1(x) teach me how to solve this
?
what do you mean ?
solve what? f^–1(x) equal: x/f ? fine
domain= R (all real numbers)
example: \[\LARGE f^{-1}(x)=\frac{2x-3}{x+1}\]
inverse right?
root: x = 0 f different 0
inverse yes, i need to learn to solve inverse problems by tomorrow
you have to replace all x-es with y and y with x... so you need to change their places and you'll have... from: \[\LARGE f^{-1}(x)=\frac{2x-3}{x+1}\] which is : \[\LARGE y=\frac{2x-3}{x+1}\] now change their places: \[\LARGE x=\frac{2y-3}{y+1}\] and now solve for y .... \[\LARGE x=\frac{2y-3}{y+1}\] \[\LARGE x(y+1)=2y-3\] \[\LARGE xy+x=2y-3\] \[\LARGE xy+x-2y=-3\] \[\LARGE xy-2y=-3-x\] \[\LARGE y(x-2)=-3-x\] \[\LARGE y=\frac{-3-x}{x-2}\]
omg uhhh ok then but how do you know what f^-1(x)= in the first place
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