Question

Phase Shift for this equation?
y=sin(pi x + pi/2)

Answer 1

is pi/2 right ??

Answer 2

See if this helps http://www.wolframalpha.com/input/?i=y%3Dsin%28pi+x+%2B+pi%2F2%29

Answer 3

y=sin(pi x + pi/2)
y=sin(3pi x / 2)

Answer 4

or
y=sin(3/2 * pi x)

Answer 5

satellite please make it short lol >.<!

Answer 6

lol jk jk :D

Answer 7

instead of memorizing formula, you can do this as follows.
you know the period of sine is \(2\pi\) and every thing happens over the interval \([0,2\pi]\) so you can set
\[\pi x+\frac{\pi}{2}=0\] solve for x and then set
\[\pi x+\frac{\pi}{2}=2\pi\] solve for x and get period and phase shift that way
on the other hand if you want a formula you can write
\[\sin(\pi x +\frac{\pi}{2}=\sin(\pi x+\frac{1}{2})\] and see that the period is now 2 and the phase shift is one half

Answer 8

did u look at the website @Ala123

Answer 9

\[\sin(\pi x +\frac{\pi}{2})=\sin(\pi (x+\frac{1}{2}))\]

Answer 10

yeah i looked but im still confused @@

Answer 11

good idea. you will see that you have a function that looks just like cosine, but with a period of 2 instead of \(2\pi\)

Answer 12

yeah the period and amplitude i got it, but the phase shift....btw the answer for phase shift is -1/2 ? why u have 1/2 ?

Answer 13

k

Answer 14

@satellite73 why the answer is -1/2 ? :|