Question

derive the equation.

Answer 1

Senx? What kind of math is this? :o

Answer 2

Is that supposed to be sin x?

Answer 3

sorry, it's in portugese :)
and yes it is.

Answer 4

Probably. But what is the question asking for? Derive it from...?

Answer 5

Okay, so \(g(x)=(\sin x+\sqrt{x})^3\cdot\sqrt{x^4+2}\) and you're looking for \(g'(x)\)?

Answer 6

no wonder i have seen these sen x for a lot of times i thought they taught secret trigonometry to people -___-

Answer 7

So, use the product rule and the chain rule, yeah? Which part are you getting stuck at?

Answer 8

i'm sorry for taking long. I was tryig to do it by myself. I just can't do it lol

Answer 9

Show us your work so we can see where you're getting lost.

Answer 10

First step, product rule, right? So \(f(x)=(\sin x+\sqrt{x})^3, g(x)=\sqrt{x^4+2}\), and we're finding \(f'(x)g(x)+g'(x)f(x)\)

Answer 11

yeeah

Answer 12

\[g(x) = (\sin x + \sqrt x)^3 *\sqrt {x^4 +2}\]This gets messy...\[\frac {dg}{dx} = (\sin x + \sqrt x)^3 \frac {d}{dx} \left[ \sqrt {x^4 +2} \right] + \sqrt {x^4 +2} \frac {d}{dx} \left[ (\sin x + \sqrt x)^3 \right]\]

Answer 13

As nbouscal said, where do you get stuck?

Answer 14

yeah, i get lost in all the algebra.

Answer 15

i just erased it all, let me try again lol.

Answer 16

Take it one step at a time. First step is to find f'(x), so derive \((\sin x + \sqrt x)^3\) using the chain rule.

Answer 17

thank you for the help :))