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Mathematics 15 Online
OpenStudy (anonymous):

1/3 + 5/n = 6/n

OpenStudy (lgbasallote):

you're asking for....n...?

OpenStudy (anonymous):

yea

OpenStudy (lgbasallote):

multiply every term by n so it'll go to the numerator...it's smooth sailing after that

OpenStudy (callisto):

I won't do that first :P 1/3 + 5/n = 6/n 1/3 = 6/n - 5/n 1/3 = 1/n It becomes easy now :)

OpenStudy (lgbasallote):

riiighht "easy" hahaha =))

OpenStudy (lgbasallote):

well whichever method you find easier @helpmeplease1179

OpenStudy (callisto):

As you get 1/3 = 1/n, you can compare the term, or really solve it. If you compare the term, just skip one step and write n=3 immediately :P

OpenStudy (zepp):

Sorry, lgba, but I prefer Callisto's method :P

OpenStudy (lgbasallote):

well you're not the asker :p

OpenStudy (anonymous):

i got n=3 thanks

OpenStudy (lgbasallote):

which method did you use @helpmeplease1179 ???

OpenStudy (anonymous):

callisto he/she i can trust ;)

OpenStudy (zepp):

But your is exactly the same 1/3n + 5 = 6 1/3n = 1 n = 1/(1/3) n = 1*3 n = 3 ;P

OpenStudy (anonymous):

:(

OpenStudy (zepp):

Poor lgba ;(

OpenStudy (anonymous):

do this zepp with that -10/2f = 20/f+100

OpenStudy (zepp):

\(\frac{-10}{2f} = \frac{20}{f}+100\) Now use lgba's method, multiply everybody by f \(\frac{-10}{2f}*f = \frac{20}{f}*f+100*f\) \(-5 = 20 +100f\)

OpenStudy (lgbasallote):

hear out my method!!! please!! \[\Large [\frac{1}{3} +\frac{5}{n} = \frac{6}{n}] n\] \[\Large \frac{n}{3} + 5 = 6\] \[\Large \frac{n}{3} = 6 - 5\] \[\Large \frac{n}{3} = 1\] \[\Large n = 3\] see?? :(

OpenStudy (anonymous):

oooooooooooooooooooooooooooooooooo u are quiet a smart gentalman

OpenStudy (anonymous):

now turn thar frown upside down

OpenStudy (callisto):

-10/2f = 20/f+100 ... If it is \[ \frac{-5}{f} = \frac{20}{f}+100\] Then... First, simplify the term on LHS -5/f = 20/f+100 Same trick again :P -5/f -20/f= 100 -25/f = 100 f= -1/4

OpenStudy (lgbasallote):

-___- this is not the end @Callisto =_= this shall come out in my next tutorial >:)) and then we'll see which they like better mwahahaha

OpenStudy (zepp):

With lgba's method -5 = 20+100f -25 = 100f f = -25/100 f = -1/4 :D

OpenStudy (anonymous):

LOL

OpenStudy (lgbasallote):

see?? isnt it easy?? :(

OpenStudy (callisto):

If it is\[ \frac{-5}{f} = \frac{20}{f+100}\] Then \[ \frac{-5}{f} = \frac{20}{f+100}\] -5 (f+100) = 20f -5f - 500 = 20f -500 = 25f f= -20

OpenStudy (anonymous):

let me try 6/p+1=7/p^2

OpenStudy (callisto):

The power is not the same, you must multiply all terms by p^2

OpenStudy (anonymous):

um..... im stuck -____-

OpenStudy (lgbasallote):

or just cross multiply :p haha we're inverting methods now

OpenStudy (anonymous):

lool

OpenStudy (lgbasallote):

oh wait is that (6/p) + 1 or 6/(p+1)??

OpenStudy (callisto):

\[ \frac{6}{p+1}=7/p^2\] Or (6/p)+1=7/p^2 ?

OpenStudy (anonymous):

yea u cant crooss muliphply

OpenStudy (anonymous):

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