Question

A certain material decays at a rate of 0.92% per year. How much of 260 grams of the material will be left in 11 years?

Answer 1

26.31 is what i get

Answer 2

can you show me your work? My teacher is a stickler for that XP

Answer 3

260 x (.92% x 11) But i am not sure if that is right, get it double checked

Answer 4

yes, use the formula N(t)=N(0)e^-kt
N((t)=260e^(-0.92/100)t at t=11 years therefore
N(11)= 260^(-0.92/100)(11)=234.98 gr approx

Answer 5

for decay formula use N(t)=N(0)e^-kt
for growth formula use N(t)=N(0)e^kt

Answer 6

any questions guys?

Answer 7

I put the following and got the same answer.
My question is if the rate percentage of decay is to be changed from a percent to a real number before computation. I did that.

N = 260 * e ^- ((.0092)(11))
N = 234.976

Answer 8

yeheyyy
correct
well lets all have more fun lol.....

Answer 9

:))