Question

If 0 degrees ≤ A ≤ 180 degrees, and tan A=-√3, how do I find the value of sinA?

Answer 1

why is √3 the opposite and 1 the adjacent? ahh..

Answer 2

there is an angle \(A\) with \(\tan(A)=-\sqrt{3}\) find the hypotenuse by pythagoras and then take the usual ratios

Answer 3

to ask is to answer, yes?

Answer 4

ohh, yes.

Answer 5

hypotenuse is
\[\sqrt{\sqrt{3}^2+1^2}=\sqrt{4}=2\] and all should be good from there. just keep in mind that you are in quadrant II so sine is positive but cosine is negative

Answer 6

ohhh.. alright. By the way, do I have to memorize special triangles and their angles? For ex. sin60 degrees = √3/2.

Answer 7

it certainly wouldn't hurt. they are all on the cheat sheet i am attaching. take a look

Answer 8

ohh, thank you!

Answer 9

yw