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what is the point- slope form of (-2,11) and (6,7)
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well you would find the slope of (-2,11) and (6,7) first
i might have it right i got y+4=-1/2(x-8)
thanks
wait no
you plug in (-2,11) or (6,7)
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not what you plugged in :/
Slope is: \[m=\frac{y_1-y_2}{x_1-x_2}\] \[m=\frac{11-7}{-2-6}\] \[m=\frac{4}{-8}\] \[m=-0.5\] So you are right. Then for point-slope form; \[y-y_1=m(x-x_1)\] Then just plug in a set of points into y1 and x1, ex: \[y-7=-0.5(x-6)\]
oh i had it backwards
Yeah you can plug either point doesnt' matter
got it
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