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Physics 19 Online
OpenStudy (anonymous):

a bullet plunges vertically into a retarding medium with an initial velocity u. its velocity is reduced by 20% in a distance of 0.9m in the medium if a is the uniform retardation in the medium then the distance is 2.5 the distance is 1.6 its avg velocity is root5a/2 the time of travel in the medium is root 5/a there are one or more answers correct

OpenStudy (anonymous):

the equation of motion here is \[x= x _{0}+v _{0}t-at ^{2}/2\]

OpenStudy (anonymous):

what x0

OpenStudy (anonymous):

\[x _{0}=0\] \[v _{0}=u _{0}\]

OpenStudy (anonymous):

ok,,,,,,,,then

OpenStudy (anonymous):

Next you must calculate acceleration using info about movement of first 20% of distance

OpenStudy (anonymous):

and motion equation

OpenStudy (anonymous):

then you will get acceleration in terms of u0

OpenStudy (anonymous):

stop there is an easier way to find acceleration

OpenStudy (anonymous):

\[a=(v _{f}-v _{i})/t\]

OpenStudy (anonymous):

for the first 20% of path vf=0.8u0 vi=u0

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then

OpenStudy (anonymous):

put the acceleration expression in motion equation and get the result

OpenStudy (anonymous):

hey how vf=0.8u0 i think 0.9

OpenStudy (anonymous):

its velocity is reduced by 20% in a distance of 0.9m

OpenStudy (anonymous):

so it is 0.18

OpenStudy (anonymous):

No velocity reduced by 20% means that it is initially was 100 % U0 then it became 80%U0=0.8U0. See?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

go on

OpenStudy (anonymous):

got it)))

OpenStudy (anonymous):

the answer is a

OpenStudy (anonymous):

for this question there is more than one answer we have to find all of them we have to check each and every options

OpenStudy (anonymous):

ok a=(vf-vi)/t so let's assume that first 0.9m of path was travelled during t1 a = -0.2U0/t1

OpenStudy (anonymous):

and put it in motion equation

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can u write whole answer completely so it will be easy to understand

OpenStudy (anonymous):

then you will get \[0.9 m = u_{0}t_{1}-(u_{0}/5t_{1})t_{1}^2/2\] \[t_{1}=1m/u_{0}\] but \[a=-u_{0}/5t_{1}\] now \[a=u_{0}/5m\] next \[v=v_{0}+at=v_{0}-(u_{0}/5m)t\] we know that when bullet stops at \[t_{final}\] its speed is zero so \[0=v_{0}+at=v_{0}-(u_{0}/5m)t_{final}\] we get \[t_{final}=5m/u_{0}\] now you are ready to find the whole distance traveled by bullet during time interval \[t_{final}\] try to solve it yourself

OpenStudy (anonymous):

thanxx

OpenStudy (anonymous):

Not at all!

OpenStudy (anonymous):

Let's try to find if another options are correct

OpenStudy (anonymous):

oops \[a=-u_{0}^2/5m\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the second option is not correct because the distance is different. the third and fourth option are obviously not correct because you can't take root of the negative value.

OpenStudy (anonymous):

the answer for this is a c d

OpenStudy (anonymous):

c is correct only when the sign of a is "+"

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the same with d

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