Question

What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)

Answer 1

y=mx+b
m=y(2)-Y(1)/x(2)-x(1)

Answer 2

The slope of the line is {1-(-3)}/(3-1)=2.
Therefore y=2x +c.
substitute (3,1) in this as the point lies on the line.
1=6+c.
c=-5
eqn required is y=2x-5

Answer 3

the 1's and 2's are subscripts

Answer 4

slope = difference in y values / difference in x values

== (1-(-3) / 3 -1) = 4/2 = 2

now use general form
y-y1 = m(x-x1) where m=slope and (x1,y1) = (3,1)