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Find f' (x) for f(x) = log6(x9+1)
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do you mean log to base 6 of (x^9 + 1)?
or log to base e (ln) of 6(x^9 + 1)?
yes I do mean log to base of ( x^9 +)
to the base 6?
yes
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i'll have to check this out...
ok
right - i'd forgotten that bit of calculus (log6 x)' = 1/ ln 6 * 1 /x so we need to use the chain rule as x is replaced by (x^9 + 1)
ok its cool
so its (1/ln 6) * 1/(x^9 + 1) * 9x^8 = 9x^8 ----------- ln 6 ( x^9 + 1)
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agreed?
Thank you soo much that is the answer my exam is a take home multi choice
your welcome - you are cool with the chain rule?
yea
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