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Mathematics 9 Online
OpenStudy (anonymous):

Find f' (x) for f(x) = log6(x9+1)

OpenStudy (cwrw238):

do you mean log to base 6 of (x^9 + 1)?

OpenStudy (cwrw238):

or log to base e (ln) of 6(x^9 + 1)?

OpenStudy (anonymous):

yes I do mean log to base of ( x^9 +)

OpenStudy (cwrw238):

to the base 6?

OpenStudy (anonymous):

yes

OpenStudy (cwrw238):

i'll have to check this out...

OpenStudy (anonymous):

ok

OpenStudy (cwrw238):

right - i'd forgotten that bit of calculus (log6 x)' = 1/ ln 6 * 1 /x so we need to use the chain rule as x is replaced by (x^9 + 1)

OpenStudy (anonymous):

ok its cool

OpenStudy (cwrw238):

so its (1/ln 6) * 1/(x^9 + 1) * 9x^8 = 9x^8 ----------- ln 6 ( x^9 + 1)

OpenStudy (cwrw238):

agreed?

OpenStudy (anonymous):

Thank you soo much that is the answer my exam is a take home multi choice

OpenStudy (cwrw238):

your welcome - you are cool with the chain rule?

OpenStudy (anonymous):

yea

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