Question

Please help with (e^x)^x*e^28=e^11x

Answer 1

\[(e ^{x})^{x}\times e ^{28}=e ^{11x}\]
Is this it?

Answer 2

Yes

Answer 3

Take logs of both sides as follows:\[x ^{2}+28=11x\]
Reaarange to form a quadratic and solve:
\[x ^{2}-11x+28=0\]
(x - 7)(x - 4) = 0
x = 7 and x = 4

Answer 4

Very smooth work there.....

Answer 5

Thx citizen :)

Answer 6

I got ut right then, how bout 4^-x= 1/256, and 8^x-1.=64^2x

Answer 7

These are a little different. Note that the bases on both of these problems are compatible. I'll do the first one, you should be able to follow on the second.\[4^{-x}= 1/256 \implies (2^2)^{-x}=2^{-8} \implies -2x=-8 \implies x=4\]

Answer 8

kropot72, not right on this one.

Answer 9

Sorry. Please give medal to AnimalAin

Answer 10

No sweat. Just trying to be a team player here....

Answer 11

vanessam: Have you got that?

Answer 12

?

Answer 13

-1/3

Answer 14

Nice job.