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OpenStudy (anonymous):
\[A ^{3}(B-C)+B^{3}(C-A)+C^{3}(A-B)\]
OpenStudy (anonymous):
\[ (A - B) (A - C) (B - C) (A + B + C) \] ;) Don't suspend me for the name of ... :P
OpenStudy (experimentx):
wow!!
OpenStudy (anonymous):
you are here by banished from the grounds of openstudy website
OpenStudy (anonymous):
lol, it's not that hard, expanding that thing will give \[ A^3 B - A B^3 - A^3 C + B^3 C + A C^3 - B C^3 \] now it's just patience and algebraic manipulation.
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OpenStudy (anonymous):
nice work though
OpenStudy (anonymous):
looking at the problem, can you tell B-C, A-B and C-A are its factors?
OpenStudy (anonymous):
I can tell now :P
OpenStudy (anonymous):
no before that!!
OpenStudy (anonymous):
well i just wanted a different solution. so I posted it here
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OpenStudy (anonymous):
No, I like your problem.
OpenStudy (anonymous):
How you solved it?
OpenStudy (anonymous):
the way i told
the moment i saw it i knew that those three are factors. it has a degree 4. so it should have another factor
i just did some mathematical manipulation which gave me the answer