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Simplify 3/x+1 + 4/x-2 Can someone show me how to solve this?
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solve as in "add"?
yes
\[\frac{3}{x+1}+\frac{4}{x-2}=\frac{3(x-2)+4(x+1)}{(x+1)(x-2)}\] then some algebra to clean up the numerator
What was the first step?
the first step is to add like you would add two fractions \[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{ad}\] in this case \(a=3, b=x+1, c=4, d=x-2\)
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Do I distribute in the numerators?
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