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Integration by trig sub help
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\[\int\limits_{}^{}{1 \over t^2\sqrt(t^2+9)} dt\]
|dw:1336605158554:dw|
I'm not sure if it's 100% integration by trig sub.. I did that way and got to integral secu/(3tan^2u)du but I'm stuck here @matt1888 sorry I couldn't use the equation thing on the question..
I labeled this triangle this way such taht when we find the other side we get that thing inside of the square root (Well along with the square root-haha) But anyways to relate those three measurement in the right triangle we will need \[\tan(\theta)=\frac{t}{3}\]
Use substitution t= a tan(s)
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