Question

Dad is 4 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim?
If D = dad's age now and J = Jim's age now, which of the following systems could be used to solve the problem?
D = 4J and D + 10 = 2J + 20
D = 4J and D + 10 = 2(4J + 10) + 20
D = 4J and D + 10 = 2(J + 10) + 20

Answer 1

well as you can see the only difference in your choices is when it came to dad's age in 10 years

Answer 2

first of all...how old is jim in 10 years? (algebraically)

Answer 3

then it says twice that...so two times jim's age in 10 years

Answer 4

then it says 20 years more than so it's + 20

(two times jim's age in 10 yrs) + 20

do that in algebra in terms of J

Answer 5

Note: Jim's age in 10 years means Jim's age now plus 10 years

Answer 6

i'll let you do the rest...it was so hard to avoid giving the answer :)