Find the average value over the given interval. f(x) = x^2 - 5x + 5; [0, 8]
How would you work this out?
Find the total area, then divide by the width. That should give you the average height.
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how would i find the area?
you need to determine the slope of the line between 2 points; (0,f(0)) and (8,f(8))
unless im reading this wrong .... which is highly possible
http://faculty.up.edu/wootton/Calc2/Section6.5.pdf if smooth is reading it better, this might help
I don't think that helps you, Amistre... Does it?
It would help you if you were trying to find the average rate of change.
yeah, which is why i have my doubts on my interpretation of the question :) yours does sound more in line with it.
\[ave=\frac{1}{b-a}\int\limits_{a}^{b}f(x)dx=\frac{1}{8}\int\limits_{0}^{8}(x^2-5x+5)dx\]Let me know if you need help evaluating this integral
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