using cyclindrical shell method, find the volume generated by rotating the region bounded by $y = \sqrt x$, y = 0, x = 1 about x = -1

my equation is $$2\pi \int_0^1 (x+1)(\sqrt x) dx$$

is that right @experimentX ?

Question

using cyclindrical shell method, find the volume generated by rotating the region bounded by $y = \sqrt x$, y = 0, x = 1 about x = -1

my equation is $$2\pi \int_0^1 (x+1)(\sqrt x) dx$$

is that right @experimentX ?

experimentx · Answer

Let's draw picture first ...

callisto · Answer

I think you should use disc method?! Not sure, you know, I'm never good at this

lgbasallote · Answer

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lgbasallote · Answer

disk method will only work  if it's perpendicular to the axis of revolution @Callisto

lgbasallote · Answer

i think...i dont know...im not good at this either

callisto · Answer

I meant with the equation y=sqrtx
I'd better shut my mouth up :|

anonymous · Answer

Shell method is easiest. Pick out an x, draw the thing that's getting rotated for that specific x, then figure out what the radius and height are.

experimentx · Answer

axis of rev??

lgbasallote · Answer

i think im sure about the radius...just not sure bout the limits and the function...lol @Callisto :p

lgbasallote · Answer

x = -1 is the axis of rev

anonymous · Answer

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