Question

A building lot in a city is shaped as a 30-60-90 triangle. The side opposite the 30 angle measures 41 feet.

a. Find the length of the side of the lot opposite the 60 angle.
b. Find the length of the hypotenuse of the triangular lot.
c. Find the sine, cosine, and tangent of the 30 angle in the lot. Write your answers as decimals rounded to four decimal places.

Answer 1

in 30-60-90 triangles, the sides are in the following ratios: x:xsqrt3: 2x wit x being the side opposite the 30 deg angle and 2x being the hypotenuse.

Can you go from here?

Answer 2

a.?

b. the hypotenuse is 82ft

c. sin(30) =0.5000
cos (30)= 0.8660
tan (30)= 0.5773

Answer 3

See, if the side opposite 30 degree is x, then the side opposite to 90 is 2x and side opposite to 60 is x*sqrt3

So, the sides are:

\(\Large \color{purple}{\rightarrow 41, 82, 41\sqrt3 }\)

Answer 4

Answer to a is mentioned.

Answer 5

wuts the answer? ._.

Answer 6

\(\Large \color{purple}{\rightarrow 41 \sqrt3 }\)

Answer 7

71.014?