Question

(1+sinx)/cosx + (cosx/(1+sinx)=2secx

Answer 1

just add the fractions together and simplify (use cos^2 + sin^2 = 1)

Answer 2

im still confused as to how i add these together.

Answer 3

Just take the denominator as cosx(1+sinx) and proceed as usual....

Answer 4

oh, so i can leave it like that without distributing it?

Answer 5

so far i get: (1+sin+cos)/(cos)(1+sin)

Answer 6

Your numerator is not correct.
Just do it as if they were normal fractions.

Answer 7

use this fact:\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

Answer 8

i get 1+2sin+sin^2+cos^2. does this look better for the numerator?

Answer 9

Yes.

Answer 10

As I said in my first post, now simplify (and use cos^2 + sin^2 = 1)

Answer 11

(1+2sin+sin^2+cos^2)/(cos)(1+sin) so far

Answer 12

now i get (2+2sin)/(cos)(1+sin)

Answer 13

There is a fairly obvious simplification there....

Answer 14

You are almost done....