please divide x^2-x-14 by x-4
first rewrite it as ______________ x - 4 | x^2 - x - 14 now...what is x^2 divided by x?
x
good x ______________ x - 4 | x^2 - x - 14 now we multiply x to each term of x - 4 x ______________ x - 4 | x^2 - x - 14 x^2 - 4x --------------- we subtract can you subtract x^2 - x - (x^2 - 4x)?
yes would it simplify to -5x?
-5x? hmm remember you distribute the minus sign... x^2 - x - x^2 - (-4x) it becomes x^2 - x - x^2 + 4x
ok got it so then you would subtract x from 4x?
yup!!
so what do you have?
I believe 3x because the x^2s cancel out ?
you got it! x ______________ x - 4 | x^2 - x - 14 x^2 - 4x --------------- 3x now we bring down 14 x ______________ x - 4 | x^2 - x - 14 x^2 - 4x --------------- 3x - 14 then we repeat the process...divide 3x by x
3?
good.. x + 3 ______________ x - 4 | x^2 - x - 14 x^2 - 4x --------------- 3x - 14 now multiply 3 to each term of x - 4
would it be 3x-12?
yup!
x + 3 ______________ x - 4 | x^2 - x - 14 x^2 - 4x --------------- 3x - 14 3x - 12 -------- subtract again
thank you so much, could you help me with solving rad72-rad50?
do you know the rest for that one?
remember to put the remainder :D
do you mean the division problem is not finished
haha yeah :))
you still have to subtract 3x - 12 from 3x - 14
so the final answer is -2?
we still have to write -2 as a remainder to do that we write \[\frac{remainder}{divisor}\] since our remainder is -2 and our divisor is 2x + 1 it becomse \[\frac{-2}{2x+1}\] got it? we add that to the quotient we have so it's \[\large x + 3 - \frac{2}{2x+1}\]
for more info on dividing polynomials by binomials check this out (a tutorial i made myself :D) http://openstudy.com/updates/4f9c9dace4b000ae9ed1966f now...as for your second question...please post in another question because long threads tend to be laggy
ok thanks |dw:1336698507854:dw|
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